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I am using several analog multiplexers to switch signals from a potentiostat to various electrodes. I am powering the MUXs with 0V and 5V and the impedance spectroscopy output from the potentiostat signal sits at 1.6 V +/- 10 mV. I need to make it so that the electrodes don't float significantly far from the signal so I would like to fix the open MUX outputs to the same voltage as the potentiostat.
Is there a good way to do this? An idea I have is to extract the potentiostat signal (Vref) using a sample and hold circuit, and then using a bunch of 1:1 MUX to short Vref to the open outputs. Then I could use decoders to close all the 1:1 MUX channels except for the currently active electrode that is being measured by the potentiostat.
An issue I foresee with this method is that if Vref changes, my electrode potentials will change which could affect the measured results. I am open to tips or better ideas of how to go about this.
Edit:
I added a schematic of my idea. Importantly the electrodes are patterned on a chip that sits in an electrolyte, so there is no electrical connection between them.
I am currently using a MAX396 16:1 MUX because it has fairly low channel capacitances and moderate on resistance. I need to make sure I don't have excess parasitic capacitance or else I will be unable to take impedance measurements. The on resistance is less important for my application, but lower is better.
I just started looking at 1:1 analog switches, so I don't know what component I would use. I'm sure I need something with very low leakage current though.