Per instance world matrix is 0.0f/NaN

Question

I'm trying to draw some cubes with Hardware Instancing.

However they don't get displayed. So I debugged my code, and found the source of the problem:

In my VertexShader, the var that has the per instance world matrix has a value of:

{ 0.0f, 0.0f, 0.0f, 0.0f, 0.0f, 0.0f, 0.0f, 0.0f, 0.0f, 0.0f, 0.0f, 0.0f, 0.0f, NaN, NaN, NaN }

The weirdest thing is that it outpus NaN (Not a Number). Here's how I create my instanced buffer:

XMMATRIX trans[4];

trans[0] = XMMatrixTranslation(0.0f, 0.0f, 0.0f);
trans[1] = XMMatrixTranslation(0.5f, 0.5f, 0.5f);
trans[2] = XMMatrixTranslation(-0.5, -0.5, 0.5);
trans[3] = XMMatrixTranslation(0.5, -0.5f, 0.5);

//Store world matrices
for (int i = 0; i < 4; i++)
    XMStoreFloat4x4(&mIV[i].world, trans[i]);

D3D11_BUFFER_DESC instDesc;
ZeroMemory(&instDesc, sizeof(D3D11_BUFFER_DESC));
instDesc.BindFlags = D3D11_BIND_VERTEX_BUFFER;
instDesc.Usage = D3D11_USAGE_DYNAMIC;
instDesc.ByteWidth = sizeof(XMFLOAT4X4) * 4;
instDesc.CPUAccessFlags = D3D11_CPU_ACCESS_WRITE;

//Create instanced buffer
HR(mDevice->CreateBuffer(&instDesc, NULL, &mBoxInstB));

Here's how I map the instanced data to my buffer:

D3D11_MAPPED_SUBRESOURCE mapSub;
mContext->Map(mBoxInstB, 0, D3D11_MAP_WRITE_DISCARD, NULL, &mapSub);

VertexI* idata = reinterpret_cast<VertexI*>(mapSub.pData);

idata = mIV;

mContext->Unmap(mBoxInstB, 0);

Thanks for the help! If you need some more info, write it in the comments!

Stephane Hockenhull · Accepted Answer · 2014-12-07 13:30:43Z

1

The issue seem to be that you don't copy data over, you're overwriting the idata pointer with the address of mIV:

idata = mIV; // this changes idata to point to mIV, not copy data

Should be something like:

for(size_t i=0; i < (sizeof(mIV) / sizeof(mIV[0])); ++i){
  idata[i] = mIV[i];
}

Or

memcpy(idata, mIV, sizeof(mIV));

Or some other copy function to copy the whole array. I'm assuming mIV is an array and not a pointer, if it is a pointer you need to use

for(size_t i=0; i < 4; ++i){
  idata[i] = mIV[i];
}

Ideally replace 4 with a constant or variable to keep track of the number of instances.

answered Dec 7, 2014 at 13:30

Stephane Hockenhull

12.1k1 gold badge26 silver badges44 bronze badges

\$\begingroup\$ Thanks for that! Now I know ;D. Any other copy function still gives the same results unfortunately..... \$\endgroup\$

Rakete1111
– Rakete1111

2014-12-07 14:59:39 +00:00
Commented Dec 7, 2014 at 14:59

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