I'm building a tool in python and for that I have a question:
I have a string such as "Denver.dwg Group Layer\Denver.dwg Annotation".
How do I assign to a variable (for later print) only the first part of the string, "Denver.dwg" ?? I need to provide a general solution, as the city name differs from case to case (it might be shorter or longer) and so counting the places until the g of dwg (10 places) won't help.
(I'm writing the python tool for arcgis 9.3.1)
The code below searches for the first occurence of the ".dwg" string and assigns a new substring (containing characters up to and including that occurence).
text = "Denver.dwg Group Layer\\Denver.dwg Annotation"
ext = ".dwg"
fileNameOnly = text[:text.find(ext) + len(ext)]
print fileNameOnly
This is very basic Python string manipulation. There are loads of quick references which will help you with these most commonly used functions, for example Python Basics, Section 5: Strings.
You should be able to use this string.find method, see my example below.
s = 'Denver.dwg Group Layer/Denver.dwg Annotation"'
# this returns lowest index of first occurence of dwg
# in this case 7
idx = s.find('dwg')
print idx
# take this index and add 3 for 'dwg'
# get desired string
subs = s[:idx+3]
print subs
str = "Denver.dwg Group Layer\Denver.dwg Annotation"
you can use split
['Denver.dwg Group Layer', 'Denver.dwg Annotation']
the result is a list
d = c[0].split(".") # first term of the list ie 'Denver.dwg Group Layer'
['Denver', 'dwg Group Layer']
d[0] # first term of the list
'Denver'
['Denver.dwg', 'Group', 'Layer\Denver.dwg', 'Annotation']
'Denver.dwg'
and
g = f.split(".")
['Denver', 'dwg']
g[0]
'Denver'
look at Dive Into Python
