2
$\begingroup$

I have the following basic question. I have created the following lists of number

list1= {0.17280394634580676`, 0.16592518527179198`,  0.16565012961313136`, 0.16913887913796202`, 0.17532555997800134`, 0.1709799900459552`, 0.1727886004102705`, 0.17309929761671264`,  0.16684725512423282`, 0.19030846458674544`}
list2 = {0.17386342603139585`, 0.19088582236184554`, 0.23203374070590962`, 0.2369946021621591`, 0.1952022726800119`, 0.23686981987007244`, 0.1980693337605245`, 0.23829147261528855`,   0.14379878667926133`, 0.18123073864910402`}

and i want to select only these elements that have simultaneously a larger value from 0.17 in list1 and a value that is lower than 0.19 in list2 and append them in a new list.

Any ideas?

Improve this question
$\endgroup$

1 Answer 1

Reset to default
3
$\begingroup$ 
criteria = {criterion1, criterion2} = {GreaterThan[.17], LessThan[.19]};

Join @@ MapThread[Select[#]@#2 &, {criteria, {list1, list2}}]

{0.172804, 0.175326, 0.17098, 0.172789, 0.173099, 0.190308, 
 0.173863,0.143799, 0.181231}

"how can I also find the positions in lists1 and 2 of each element that is appented in the joint list?"

KeySelect[criterion1] @ PositionIndex[list1]

<|0.172804 -> {1}, 0.175326 -> {5}, 0.17098 -> {6}, 0.172789 -> {7}, 

 0.173099 -> {8}, 0.190308 -> {10}|>

KeySelect[criterion2] @ PositionIndex[list2]

<|0.173863 -> {1}, 0.143799 -> {9}, 0.181231 -> {10}|>
Improve this answer
$\endgroup$
3
  • $\begingroup$ Dear kglr thank you for your quick response. This is a really nice solution! Do you have any idea, how can I also find the positions in lists1 and 2 of each element that is appented in the joint list? $\endgroup$ Commented Jun 17, 2020 at 9:50
  • $\begingroup$ @Smaug, please see the update. $\endgroup$ Commented Jun 17, 2020 at 9:55
  • 1
    $\begingroup$ Thank you very much for your time. This is exactly what I was looking for! :D $\endgroup$ Commented Jun 17, 2020 at 9:58

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.