Hi I need help with the method that follows: var ages = [3, 10, 18, 20];
function checkAdult(age) { return age >= 18; }
function myFunction() { document.getElementById("demo").innerHTML = ages.findIndex(checkAdult); }
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didn't get the proper answerraman– raman2020-07-07 13:04:36 +00:00Commented Jul 7, 2020 at 13:04
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Please edit your existing post to clarify. Don't repost.David Reed– David Reed2020-07-07 15:26:09 +00:00Commented Jul 7, 2020 at 15:26
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1 Answer
It's entirely possible that the values are null instead of an empty string. There is a difference between the two (JavaScript actually has both null and undefined types that represent a missing a value). Also, findIndex is not necessary here, you can just use find:
const test = !!data.find(value => value.Fname || value.Lname);
The !! notation converts a falsy value to false and a truthy value to true without a ternary operator. A value is falsy if it is null, undefined, empty string, 0, or false, and true otherwise. This should be sufficient for your use case.
Also, I noticed a typo in your code, which I've fixed, above. Lanme is probably meant to be Lname. Pay attention to typos, as that can easily cause hard-to-detect problems in JavaScript.
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actually in the org if field value is blank then it is not present in the data aray.raman– raman2020-07-07 13:49:27 +00:00Commented Jul 7, 2020 at 13:49
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@raman That would be
undefined, not''.sfdcfox– sfdcfox2020-07-07 13:53:31 +00:00Commented Jul 7, 2020 at 13:53 -
const test = !data.some(value => !(value.Fname || value.Lname)); @raman try this.Avi Rai– Avi Rai2020-07-07 14:25:28 +00:00Commented Jul 7, 2020 at 14:25
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@sfdcfox Thnakyou soo much it is undefined!! eaten my head from 1 hourraman– raman2020-07-07 14:30:56 +00:00Commented Jul 7, 2020 at 14:30