I was about to initialize a char array inside a class as
class a{
char a[25];
};
a::a(){
a[] = {'a','b','c'};
}
but gives compile time error.
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1You can initialize it in class constructor.Arun Jain– Arun Jain2012-07-25 06:27:06 +00:00Commented Jul 25, 2012 at 6:27
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My answer on this other question might help you.Qaz– Qaz2012-07-25 06:27:28 +00:00Commented Jul 25, 2012 at 6:27
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@ArunJain thats what im doing..isnt it..second part a(){}??Shashi Bhushan– Shashi Bhushan2012-07-25 06:29:28 +00:00Commented Jul 25, 2012 at 6:29
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Does it have to be char array? Can't you use std::string?Ivaylo Strandjev– Ivaylo Strandjev2012-07-25 06:29:49 +00:00Commented Jul 25, 2012 at 6:29
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char array it has to be.Shashi Bhushan– Shashi Bhushan2012-07-25 06:30:15 +00:00Commented Jul 25, 2012 at 6:30
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2 Answers
If your compiler supports the C++11 feature, you can do it like this:
a::a() :arr({'a','b','c'})
{}
Otherwise, you'll have to do it manually, or you can use a function like memcpy:
a::a() {
memcpy(arr,"abc",3);
// The other initialization method will fill the rest in with 0,
// I don't know if that's important, but:
std::fill(arr + 3, arr + 25, '\0');
}
Or, as suggested by ephemient:
a::a() {
strncpy(arr, "abc", 25);
}
1 Comment
ephemient
Another possibility: when
strncpy is available, it always pads with \0 to fill -- strncpy(a, "abc", 25) will write 25 bytes, the last 22 of which are NUL.class LexerP
{
public:
char header[5];
void h();
void echo(){printf(" salut les gars ...\n \n");};
};
void LexerP::h()
{
int i=0;
int j=0;
char headM[5] ={0x07,0x0A,0x05,0x00,0x05};
/* for (i=0;i<strlen(this->header);i++)
header[i]=headM[i];*/
strcpy(this->header,headM)
};
main()
{
LexerP *M=new (LexerP);
M->echo();
M->h();
return 0;
}
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