Creating a struct parameter

Question

I have a struct defined as :

typedef struct pt {
  int x; 
  int y;   
}point;

I also have a stack push function declared as :

void push(point p);

Now whenever i wish to call this function, I can do the following :

point p = {x_value, y_value};
push(p);

I wanted to know if there is a less cumbersome workaround for this. Something which could enable me to do this in a single line. Maybe something like :

push((point){x_value, y_value});

Have you tried push((point){x_value, y_value}); to see if it works? — rjp
– rjp, Commented Oct 28, 2013 at 15:52
Yes, i get the error : expected primary-expression before '{' token — user1925405
– user1925405, Commented Oct 28, 2013 at 15:53
in c you have to allocate the memory. Constructors in C++ handle this. You need to create a constructor as Tilman states below. — Benjamin Trent
– Benjamin Trent, Commented Oct 28, 2013 at 15:56

Tilman Vogel · Accepted Answer · 2013-10-28 19:19:30Z

6

Define a "constructor" function:

point make_point(int x, int y)
{
    point result = {x, y};
    return result;
}

Then

push(make_point(x, y));

edited Oct 28, 2013 at 19:19

answered Oct 28, 2013 at 15:52

Tilman Vogel

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1 Comment

user529758 Over a year ago

As a C developer, it's a reflex that I think: do people really not recognize that we live after 1999?

user529758 · Accepted Answer · 2013-10-28 15:57:17Z

3

The syntax you thought of works out of the box in C99:

typedef struct {
    int x;
    int y;
} point;

push((point){ 42, 1337 });

What's even better, the resulting literal is an lvalue, so you can take its address in case your push() function accepts a pointer:

void push(point *p);

// ...

push(&(point){ 42, 1337 });

Demo here.

answered Oct 28, 2013 at 15:57

user529758

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