In php pass a string as multiple parameters

Question

in PHP i need to use this

$pdf->SetXY(56, 100);

but now i need the parameters in variables

$paramxy= "56, 100";

PHP doesn't seem to like me writing

$pdf->SetXY($paramxy);

it doesn't evaluate "$paramxw" as two separate values..

of course the easy solution would be :

$param[x]= 56; 
$param[y]= 100;
$pdf->SetXY($param[x],$param[y]);

but i'd like it to be shorter and more readable, because I need lots of these two lines..

is there a "parse" like function that I could use, for example like that ?

$pdf_paramxy= "56, 100";
$pdf->SetXY(parse($paramxy));

This smells dangerouly like eval...

Niet the Dark Absol
– Niet the Dark Absol

2013-11-08 12:59:25 +00:00
Commented Nov 8, 2013 at 12:59 — Niet the Dark Absol
– Niet the Dark Absol, Commented Nov 8, 2013 at 12:59

Community · Accepted Answer · 2017-05-23 10:24:59Z

1

Native? Not. But you can create your own:

$paramxy= "56, 100";
$params = explode(",", $paramxy);

Then, according to this, you can:

call_user_func_array(array($pdf, "SetXY"), $params);

If values of the array being a string is a problem, you can parse it by each value:

foreach($params as $key => $value)
{
    $params[$key] = (int)$value;
}

call_user_func_array(array($pdf, "SetXY"), $params);

Didn't tested it. Hope it helps.

edited May 23, 2017 at 10:24

CommunityBot

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answered Nov 8, 2013 at 11:47

DontVoteMeDown

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Comments

user2968704 · Accepted Answer · 2013-11-08 13:23:24Z

0

you can't set a value for a variable in the following manner $pdf_nomenfant= "56, 100"; To achieve your target you have two ways.

create two parameters with different values like $param1 = "56"; and $param2 = "100";

and the other way is to use an array for this task as in the following:

'$paramxy= array ("56, 100"); $pdf->SetXY(parse($paramxy));

edited Nov 8, 2013 at 13:23

user2968704

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answered Nov 8, 2013 at 11:47

user2951753

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