How to pass variable argument list in PHP

Question

I have a function that is always called like this:

old_function(sprintf("Some arbitrary data %d, %s, %f\n", $i, $s, $f));

Is it possible in PHP to make a function that combines these to functions for

new_function("Some arbitrary data %d, %s, %f\n", $i, $s, $f);

In the beginning of new_function, the variable argument list of the function would have to be parsed and passed to sprintf internally:

function new_function( /* variable argument list */ )
{
     $string = sprintf( /* variable argument list */ );
     return old_function($string);
}

Is it possible in PHP?

kero · Accepted Answer · 2014-10-15 14:01:24Z

3

You can use func_get_args() & call_user_func_array() for this:

function new_function()
{
     // get all function arguments
     $args = func_get_args();
     // run the function "sprintf" with the given arguments
     $string = call_user_func_array("sprintf", $args);
     return old_function($string);
}

edited Oct 15, 2014 at 14:01

kero

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answered Oct 15, 2014 at 13:59

Gerald Schneider

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Comments

edigu · Accepted Answer · 2014-10-15 14:25:46Z

2

As of PHP 5.6, you can try to use Variadic Functions via ... operator. This new feature enables native support for passing variable-length argument lists to any function.

Try something like this:

public function new_function(...$params) {
    $string = call_user_func_array("sprintf", $params);
    return old_function($string);
}

answered Oct 15, 2014 at 14:25

edigu

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Comments

nithin · Accepted Answer · 2014-10-15 14:01:11Z

0

Please look into func_get_args() method. Which can retrieve variable length arguments.

answered Oct 15, 2014 at 14:01

nithin

1

1 Comment

Roland Seuhs Over a year ago

That's nice, but that does not tell me how to actually pass the arguments to sprintf

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