In my php code I need to invoke a script and passing it some arguments. How can I pass php variables (as arguments) ?
$string1="some value";
$string2="some other value";
header('Location: '...script.php?arg1=$string1&arg2=$string2');
thanks
5 Answers
header('Location: ...script.php?arg1=' . $string1 . '&arg2=' . $string2);
1 Comment
KingCrunch
Not worth a new answer, but double quotes are also possible:
header("Location: http://example.com/script.php?arg1=$string1&arg2=$string2");Either via string concatenation:
header('Location: script.php?arg1=' . urlencode($string1) . '&arg2=' . urlencode($string2));
Or string interpolation
$string1=urlencode("some value");
$string2=urlencode("some other value");
header("Location: script.php?arg1={$string1}&arg2={$string2}");
Personally, I prefer the second style. It's far easier on the eyes and less chance of a misplaced quote and/or ., and with any decent syntax highlighting editor, the variables will be colored differently than the rest of the string.
The urlencode() portion is required if your values have any kind of url-metacharacters in them (spaces, ampersands, etc...)
Comments
You could use the function http_build_query
$query = http_build_query(array('arg1' => $string, 'arg2' => $string2));
header("Location: http://www.example.com/script.php?" . $query);
Comments
Like this:
header("Location: http://www.example.com/script.php?arg1=$string1&arg2=$string2");
answered Feb 16, 2011 at 14:19
Klaus Byskov Pedersen
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Comments
It should work, but wrap a urlencode() incase there is anything funny breaking the url:
header('Location: '...script.php?'.urlencode("arg1=".$string1."&arg2=".$string2).');
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