I want to have phone number in working combination of '0' followed by 10 digit mobile number (or) 0091 folllowed by 10 digit mobile number (or) +91 followed by 10 digit number.
1) 0 followed and +91 folowed numbers are working with following regex i also want 0091 followed number to be worked, my regex is:
"^([0]|(?:[0][0]|\\+)(91))([7-9]{1})([0-9]{9})$";
Could you suggest me working a regex.
The exact regex you seem to be going for (based on what you've tried so far) is:
^(?:0091|\\+91|0)[7-9][0-9]{9}$
As a general tip, to have worked this out yourself I'd advise using a site like RegExr or RegexPal
Set it to multi-line mode (so that ^ and $ match at the end of each line) then add 0091, +91 and 0 into the input box on separate lines - so you have something like this.
Then try to make a regex that matches just that part, in your case you needed something like
^0091|\+91|0$
Note: on RegExr you don't have to escape backslashes (so when you use the regex in java you need to go through escaping them).
Guess this regex would work:
^((0091)|(\+91)|(0))([7-9]{1})([0-9]{9})$
If you are working on Android, you could use this method:
PhoneNumberUtils.isGlobalPhoneNumber("+91.......)
Or try to do something like that if you really want to use regex:
if (match("^0[0-9]{9}") || match("^+91[0-9]{10}") || match("^0091[0-9]{9}"))
Use the following code (test.matches(..) ist the important part):
String test = "00911234567891";
System.out.println(test.matches("(0091|0|\\+91)[7-9][0-9]{9}"));
This regex should work.
You can use ^([0]|\+91)?\d{10} as starts with 0 or +91 and 10 digits after that.
