Build and order an array with the first element of other arrays

Question

I'm trying to transform an array of 3 arrays in an array of 4 where each array is built and ordered with the first element of each other.

I have this:

[[1, 2, 3], [4, 5, 6], [7, 8, 9], [10, 11, 12]]

And I would like the following:

[[1, 4, 7, 10], [2, 5, 8, 11], [3, 6, 9, 12]]

Any ideas?

sawa · Accepted Answer · 2014-07-17 17:31:18Z

4

Use Array#transpose.

your_array.transpose

will do it.

edited Jul 17, 2014 at 17:31

answered Jul 17, 2014 at 17:26

sawa

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6 Comments

Arup Rakshit Over a year ago

Fastest answer, I have ever seen.. :-)

sawa Over a year ago

It is (perhaps) the first time I answered in less than a minute after the post. Usually, it takes two minutes untill I see the question posted.

Cary Swoveland Over a year ago

You wouldn't want to damage your HHKB2. I suggest you let it cool for a few minutes.

sawa Over a year ago

@CarySwoveland At this particular moment, my HHKB2 is sleeping, and I am typing on Filco Majestouch.

sawa Over a year ago

@ArupRakshit I am more excited about the fact that I am very close to being in the top five Ruby answerers. I was an inactive user for the first year, and overall, it took me four years and three months to reach this position.

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George Lucas · Accepted Answer · 2014-07-17 19:14:59Z

0

array = [[1, 2, 3], [4, 5, 6], [7, 8, 9], [10, 11, 12]]
array.transpose
[[1, 4, 7, 10], [2, 5, 8, 11], [3, 6, 9, 12]]

Is this what you were looking for?

answered Jul 17, 2014 at 19:14

George Lucas

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