PHP Regex match specific site url with params

Question

I have some text, and I need to wrap my site urls into links.

Example text: "Lorem ipsum dolor sit amet, vitasya-le.work consectetur adipiscing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. http://vitasya-le.work Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat. habrahabr Duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur. vitasya-le.work"

I need to match these URLs:

http://vitasya-le.work
vitasya-le.work
http://www.vitasya-le.work
vitasya-le.work/topic/view/33113-topic-title
http://vitasya-le.work/topic/view/33113-topic-title
http://www.vitasya-le.work/topic/view/33113-topic-title
.vitasya-le.work

I have ((\S+|\s)vitasya-le.work(\s|\S+|$)) pattern but it doesn't match all combinations

Eh, .vitasya-le.work is not a valid URL...

Sverri M. Olsen
– Sverri M. Olsen

2014-10-22 10:19:32 +00:00
Commented Oct 22, 2014 at 10:19 — Sverri M. Olsen
– Sverri M. Olsen, Commented Oct 22, 2014 at 10:19

Sverri M. Olsen · Accepted Answer · 2014-10-22 10:08:07Z

Here is a regex that should match all of them:

$regex = '/(?:http:\/\/)?(?:www\.)?vitasya-le\.work(?:\/[\w\-]+)*\/?/';

And some tests:

$tests = array(
    'http://vitasya-le.work',
    'vitasya-le.work',
    'http://www.vitasya-le.work',
    'vitasya-le.work/topic/view/33113-topic-title',
    'http://vitasya-le.work/topic/view/33113-topic-title',
    'http://www.vitasya-le.work/topic/view/33113-topic-title',
);
echo '<pre>';
foreach ($tests as $test) {
    preg_match($regex, $test, $match);
    if (empty($match)) {
        echo 'Did NOT match: ', $test, "\n";
    } else {
        echo 'Match: ', $test, "\n";
    }
}

$test2 = 'Lorem ipsum dolor sit amet, vitasya-le.work consectetur '
.'adipiscing elit, sed do eiusmod tempor incididunt ut labore '
.'et dolore magna aliqua. http://vitasya-le.work Ut enim ad '
.'minim veniam, quis nostrud exercitation ullamco laboris nisi '
.'ut aliquip ex ea commodo consequat. habrahabr Duis aute irure '
.'dolor in reprehenderit in voluptate velit esse cillum dolore '
.'eu fugiat nulla pariatur. vitasya-le.work';

preg_match_all($regex, $test2, $matches);
var_dump(array_pop($matches));

Mitya · Accepted Answer · 2014-10-22 10:09:39Z

0

Try this:

$text = preg_replace(
    '/((http:\/\/(www.)?|\.))?vitasya-le\.work[\S]*/',
    '<a href="$0">$0</a>',
    $text
);

Steps:

optionally match http:// optionally followed by www., or just .
then match the main part of the URL
match any sequence of characters after the main part that aren't space characters

answered Oct 22, 2014 at 10:09

Mitya

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