Regular Expression Pattern (match URL)

Question

I need a regular expression that identify special links.

I have an array with links, for example this one

array[1] = "http://domain.com/dfdf"
array[2] = "http://domain.com/dfgf"
array[3] = "http://domain2.com/derf"

I want to use a regular expression that extract links from this array under a specific domain (for example domain2)

I'll get an array

array[1] = "http://domain2.com/derf"

I'm looking for the pattern only (I use PHP)

no, I have the links stored and they are regular, I mean they have the same format "domain.com" — Omar Abid
– Omar Abid, Commented Aug 21, 2009 at 10:57
What you like to use domain2 or domain2.com as input? should www.domain2.com also be matched by the pattern, what about https : //ssl.domain2.com/something? What about domain2.net? What about links without http in front of them? — Residuum
– Residuum, Commented Aug 21, 2009 at 10:58
Regular expressions seem a bit improper for this task. Why not just use the string functions? — Philippe Gerber
– Philippe Gerber, Commented Aug 21, 2009 at 11:02

Gumbo · Accepted Answer · 2009-08-21 10:57:07Z

2

This regular expression should do it:

^http://domain2\.com/

And converted into PCRE with / as delimiter:

/^http:\/\/domain2\.com\//

But you can use another character if you want:

~^http://domain2\.com/~

answered Aug 21, 2009 at 10:57

Gumbo

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Comments

DrAl · Accepted Answer · 2009-08-21 10:56:44Z

0

How about:

(?<!")http://domain2.com[^"]+

answered Aug 21, 2009 at 10:56

DrAl

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Residuum · Accepted Answer · 2009-08-21 11:00:24Z

0

This will match https as well as http links:

#^https?://domain2\.com/#

answered Aug 21, 2009 at 11:00

Residuum

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