Python - How to combine multiple re.sub functions into a single function?

Question

for i in (f):
    r = re.sub('.*\.f', '.wiki [href*=""], .f', i)
    s = re.sub('width', 'min-width', i)
    t = re.sub('height:40px;', '', i)

    outp.append(r)
    outp.append(s)
    outp.append(t)

As you can see, I have 3 lines of regex that work individually but it doesn't work like how I'd want to because they are appended 3 times so I need to combine them and append it once.

You also can use a single line: re.sub('height:40px;', '', re.sub('width', 'min-width', re.sub('.*\.f', '.wiki [href*=""], .f', i))). Just replace each i with another re.sub(). The inner-most re.sub() function will be evaluated first. This is the same as the answer given by Cantfindname. — colidyre
– colidyre, Commented Oct 22, 2015 at 9:30
"they are appended 3 times" - because that's exactly what you ask it to do. Have you considered reading the code before asking a question? — jonrsharpe
– jonrsharpe, Commented Oct 22, 2015 at 9:32

Cantfindname · Accepted Answer · 2015-10-22 09:22:36Z

3

Something like this?

for i in (f):
    r = re.sub('.*\.f', '.wiki [href*=""], .f', i)
    s = re.sub('width', 'min-width', r)
    t = re.sub('height:40px;', '', s)

    outp.append(t)

answered Oct 22, 2015 at 9:22

Cantfindname

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