This should be a vary basic thing to do, but I can't get it to work despite following a lot of examples from the web. What I'm trying is to use the sub function to get the name of a file from a complete path.
So, if
output="/home/alvarofeal/Desktop/prueba_sub.avi"
re.sub(r'(.*\/)*', "", output)
print output
output: /home/alvarofeal/Desktop/prueba_sub.avi
Shouldn't the output be:
prueba_sub.avi
re.sub() returns a new string. Strings are immutable and cannot be changed in-place.
You are ignoring the return value; store it back in output if you want to replace the old value:
output = "/home/alvarofeal/Desktop/prueba_sub.avi"
output = re.sub(r'(.*\/)*', "", output)
print output
If all you are doing is splitting the basename of a file path, you probably want to use the os.path.basename() function instead though.
You have to do,
output = re.sub(r'(.*\/)*', "", output)
since re.sub() returns new string
OR using ntpath
>>>import ntpath
>>>ntpath.basename(output)
'prueba_sub.avi'
You don't need regex for this task.As a more pythonic way you can use os.path.basename with str.split:
>>> os.path.basename('/home/alvarofeal/Desktop/prueba_sub.avi').split('.')[0]
'prueba_sub'
or just use basename to get the name with format :
>>> os.path.basename('/home/alvarofeal/Desktop/prueba_sub.avi')
'prueba_sub.avi'
