Converting byte array to string and back again [duplicate]

Question

I realize this question is probably idiotic, but hey, rough day. Anyway, given this:

scala> import java.nio.charset.Charset
import java.nio.charset.Charset

scala> val alpha = Array[Byte](2,-9,-7,-126,-36,-41,-16,56)
alpha: Array[Byte] = Array(2, -9, -7, -126, -36, -41, -16, 56)

scala> val beta = new String(alpha, Charset.forName("UTF-8"))
beta: String = ?������8

scala> val gamma = beta.getBytes(Charset.forName("UTF-8"))
gamma: Array[Byte] = Array(2, -17, -65, -67, -17, -65, -67, -17, -65, -67, -17, -65, -67, -17, -65, -67, -17, -65, -67, 56)

Why doesn't alpha == gamma? What's the correct way to do this?

Update: I see Base64 encoding/decoding works. But I am still interested in why UTF-8 doesn't. Perhaps it's because there is no UTF-8 representation of one or more those bytes.

Shaido · Accepted Answer · 2018-02-06 05:25:32Z

2

UTF-8 uses one-to-four byte unsigned values. You would have to figure out what UTF-8 values you are actually getting when you underflow the values like that.

If you check new String(alpha) == new String(gamma), you will see that it returns true.

edited Feb 6, 2018 at 5:25

Shaido

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answered May 1, 2017 at 20:22

GreyBeardedGeek

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