Python lambda function in sorted()

Question

This woking code gives me the 5 most relevant documents for a topic out of my corpus.

most_relevant_docs = sorted(bow_corpus, reverse=True, key=lambda doc: abs(dict(doc).get(topic_number, 0.0))) 
print most_relevant_docs[ :5]

But since the corpus is not readable by human I want to zip an index to the corpus so I can recover the depending documents.

corpus_ids = range(0,len(corpus))
most_relevant_docs = sorted(zip(corpus_ids, bow_corpus), reverse=True, key=lambda my_id, doc : abs(dict(doc).get(topic_number, 0.0)))
print most_relevant_docs[ :5]

Where do I have to adapt the lambda function so it returns the id together with the document?

Can you mock up some data so we can visualize what you are trying to achieve? Of course, as it stands, we can't run any of your code. — jpp
– jpp, Commented Jun 29, 2018 at 9:36
the lambda is used as a key only, will not modify the structure of the output but the order of it — Netwave
– Netwave, Commented Jun 29, 2018 at 9:38

user464014 · Accepted Answer · 2018-06-29 09:40:27Z

2

Try this

sortingFunc = lambda doc: abs(dict(doc).get(topic_number, 0.0))
corpus_ids = range(0,len(corpus))
most_relevant_docs = sorted(zip(corpus_ids, bow_corpus), reverse=True, key=lambda pair: sortingFunc(pair[1]))

When you zip it, each element becomes like (index, value), so the original sorting key wouldn't work. You'd need to modify it so it sorts by the value as opposed to the pair

answered Jun 29, 2018 at 9:40

user464014

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