To sort a dictionary on values, all the answers I found use a lambda. Is it possible to use a function? I can't seem to get the values passed correctly.
sales = {
'north': 2,
'south': 6,
'east': 8,
'west': 7,
}
def get_value(collection,key): # substitue for lambda x: x[1]
return collection.get(key)
print(sales)
#sort_sales = sorted(sales.items(), key=lambda x: x[1]) # uses lambda
sort_sales = sorted(sales.items(), get_value( sales,sales.items() ) )
print(sort_sales)
Have a look at what sales.items() gives you. Based on that you can do:
def get_value(item):
return item[1]
sorted(sales.items(), key=get_value)
Returns
[('north', 2), ('south', 6), ('west', 7), ('east', 8)]
get_value, you can also use operator.itemgetter(1): docs.python.org/3/library/operator.html#operator.itemgetterThe equivalent of lambda x: x[1] is
def get_value(x):
return x[1]
Generally, you can turn the lambda argument list into a function argument list and the lambda expression into a return statement, and that will suffice for any non-capturing lambda. For capturing lambdas, you'll need to make a nested function that explicitly captures the variables you want.
# (Non-specific example)
def get_value(foo):
def _function(x):
return x[foo]
# If we assume we have a variable foo defined as
foo = 1
# Then the two are roughly equivalent
fn1 = get_value(foo)
fn2 = lambda x: x[foo]
