Converting hex to binary in array

Question

I'm working on Visual Studio about python Project and The user input like that 010203 and I use this code for saparating the input:

dynamic_array = [ ] 
hexdec = input("Enter the hex number to binary ");
strArray = [hexdec[idx:idx+2]  for idx in range(len(hexdec)) if idx%2 == 0]
dynamic_array = strArray
print(dynamic_array[0] + " IAM" )  
print(dynamic_array[1] + " NOA" )
print(dynamic_array[2] + " FCI" )

So, the output is:

01 IAM
02 NOA
03 FCI

However my expected output converting this hex numbers to binary numbers look like this:

00000001 IAM
00000010 NOA
00000011 FCI

Is there any way to do this?

'{0:b}'.format(int(hex_val, 16)).zfill(8). It's a lot easier if you think of hex as a plain number. From there, you just search your way to stackoverflow.com/questions/699866/python-int-to-binary — Torxed
– Torxed, Commented Oct 16, 2018 at 9:02

Torxed · Accepted Answer · 2018-10-16 09:15:33Z

3

It's a lot easier if you thnk of hex as a integer (number).
There's a lot of tips on how to convert integers to different outcomes, but one useful string representation tool is .format() which can format a integer (and others) to various outputs.

This is a combination of:

The solutions would be:

binary = '{:08b}'.format(int(hex_val, 16))

And the end result code would look something like this:

def toBin(hex_val):
    return '{:08b}'.format(int(hex_val, 16)).zfill(8)

hexdec = input("Enter the hex number to binary ");
dynamic_array = [toBin(hexdec[idx:idx+2]) for idx in range(len(hexdec)) if idx%2 == 0]
print(dynamic_array[0] + " IAM" )  
print(dynamic_array[1] + " NOA" )
print(dynamic_array[2] + " FCI" )

Rohit also proposed a pretty good solution, but I'd suggest you swap the contents of toBin() with bin(int()) rather than doing it per print statement.

I also restructured the code a bit, because I saw no point in initializing dynamic_array with a empty list. Python doesn't need you to set up variables before assigning values to them. There was also no point in creating strArray just to replace the empty dynamic_array with it, so concatenated three lines into one.

machnic also points out a good programming tip, the use of format() on your entire string. Makes for a very readable code :)

Hope this helps and that my tips makes sense.

edited Oct 16, 2018 at 9:15

answered Oct 16, 2018 at 9:09

Torxed

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1 Comment

Asell Over a year ago

Thank you @Torxed you safe my life

Rohit-Pandey · Accepted Answer · 2018-10-16 09:09:27Z

0

dynamic_array = [ ] 
hexdec = input("Enter the hex number to binary ");
strArray = [hexdec[idx:idx+2]  for idx in range(len(hexdec)) if idx%2 == 0]
dynamic_array = strArray
print((bin(int(dynamic_array[0],16))[2:]).zfill(8)+ " IAM" )  
print((bin(int(dynamic_array[1],16))[2:]).zfill(8) + " NOA" )
print((bin(int(dynamic_array[2],16))[2:]).zfill(8) + " FCI")

answered Oct 16, 2018 at 9:09

Rohit-Pandey

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1 Comment

Rohit-Pandey Over a year ago

Welcome and Happy Coding :)

Michał Machnicki · Accepted Answer · 2018-10-16 09:12:13Z

0

You can format the string to achieve it. Your code may look like:

dynamic_array = [ ] 
hexdec = input("Enter the hex number to binary ")

strArray = [hexdec[idx:idx+2] for idx in range(len(hexdec)) if idx%2 == 0]
dynamic_array = strArray
print("{:08b} IAM".format(int(dynamic_array[0])))
print("{:08b} NOA".format(int(dynamic_array[1])))
print("{:08b} FCI".format(int(dynamic_array[2])))

answered Oct 16, 2018 at 9:12

Michał Machnicki

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