TypeScript: Cannot call super method on child class

Question

When I try to override a parent method and I use super inside, I get this error:

error TS2340: Only public and protected methods of the base class are accessible via the 'super' keyword.
    return super.toJson(["password", ...blacklist]);

This is an example:

abstract class BaseUser {
    name: string;

    constructor(name: string) {
        this.name = name;
    }

    toJson = () => {
        return Object.assign({}, this);
    }
}

class MyUser {
   ...
   toJson = (blacklist) => {
       ...
       const obj = super.toJson();
       ... 
   }
}

Don't know what I'm doing wrong...

MyUser does extend BaseUser in you code. Even if it did, toJson is not a method it is a field that is a function and thus not present on the prototype (it is assigned in the constructor) and you can't call it through super. Make it a regular method and it should work — Titian Cernicova-Dragomir
– Titian Cernicova-Dragomir, Commented Mar 29, 2019 at 17:14
I was going to post this as an answer but your comment says it all so I let you post it as an answer if you want to. — BotMaster
– BotMaster, Commented Mar 29, 2019 at 20:59
Possible duplicate of Inheritance method call triggers Typescript compiler error — Eneko de la Torre
– Eneko de la Torre, Commented Apr 3, 2019 at 11:44

Eneko de la Torre · Accepted Answer · 2019-04-03 11:54:23Z

6

As @Titian Cernicova-Dragomir said in the comments, you should use method instead. You can check these answers:

Inheritance method call triggers Typescript compiler error

Error when performing Inheritance in TypeScript

edited Apr 3, 2019 at 11:54

answered Apr 3, 2019 at 11:49

Eneko de la Torre

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