Using trim more than once in an array JS

Question

I have a snippet of code where I am trying to parse a longer string with special characters into an array with no spaces or special characters.
input: name: this is some stuff, name2: this is more stuff
desired output: [name,this is some stuff,name2,this is more stuff]
current output: z.trim isn't a function

function parseOrder(custOrder) {
  const custOrderArr = custOrder.split(','); 
  const trimedArr = custOrderArr.map((x) => x.trim());
  const numberArr = trimedArr.map((y) => y.split(':'));
  const processArr = numberArr.map((z) => z.trim());
  console.log(processArr);
}

Why does trim work the first time and not the second?

in some of the iterations your var z may not be of type string, post your dataset you're working with. — Akash Shrivastava
– Akash Shrivastava, Commented Jan 6, 2020 at 16:23
You're creating an array of arrays (stored in numberArr). Maybe you'd want to take a look at array.flatten or use regex. — Snapstromegon
– Snapstromegon, Commented Jan 6, 2020 at 16:25
numberArr looks like it is going to be an array of arrays of strings — Taplar
– Taplar, Commented Jan 6, 2020 at 16:25

Nina Scholz · Accepted Answer · 2020-01-06 16:35:57Z

2

You can not trim an array. But you could map the array and trim the values.

This result features Array#flatMap for preventing arrays with pairs.

function parseOrder(custOrder) {
    return custOrder
        .split(',')
        .flatMap(y => y.split(':').map(x => x.trim()));
}


var input = 'name: this is some stuff, name2: this is more stuff ';

console.log(parseOrder(input));

edited Jan 6, 2020 at 16:35

answered Jan 6, 2020 at 16:26

Nina Scholz

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1 Comment

Morgan Smith Over a year ago

yup, totally skipped over the fact it was an array of arrays, not just an array.

StepUp · Accepted Answer · 2020-01-06 16:48:43Z

1

Try to split by two signs, then trim your elements:

const result = str.split(/[\:,]+/).map(s => s.trim());

An example:

let str = 'test: It is me, test2: it is me 2 ';
console.log(str.split(/[\:,]+/).map(s => s.trim()));

edited Jan 6, 2020 at 16:48

answered Jan 6, 2020 at 16:34

StepUp

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