map method function javascript

Question

hello to every one i hope you have a good day :)

i need to define a function, It should accept an array of strings which may contain additional space characters.

the function should use the array map method in order to make a new array full of trimmed names.

i tried something like that but its not close to work unfortunately

function cleanNames(array) {
   const trimArray = array.map() function() {
     return array.trim();
   }
}

The callback should get the string, and you should pass the string to trim. You also forgot to return trimArray. See developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… — Ori Drori
– Ori Drori, Commented Nov 13, 2020 at 14:02

Mamun · Accepted Answer · 2020-11-13 14:23:19Z

2

Your code throws the following syntax error:

Uncaught SyntaxError: Unexpected token 'function'

in array.map() function() {

You have to trim the names inside the map callback function. You can also use arrow function (=>) syntax to shorten the code:

function cleanNames(arr) {
  return arr.map(i => i.trim());
}

console.log(cleanNames(['John ', ' Jane', ' Joe ']));

edited Nov 13, 2020 at 14:23

answered Nov 13, 2020 at 14:05

Mamun

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user14624536 · Accepted Answer · 2020-11-13 14:04:43Z

1

You should do it like this:

var array = [" Mike", " Hellen", "Robert "];
array = array.map(function (el) {
  return el.trim();
});
console.log(array);

you have to do the edit in map function.

answered Nov 13, 2020 at 14:04

user14624536

Comments

jenson-button-event · Accepted Answer · 2020-11-13 14:08:07Z

1

console.log([" Mike", " Hellen", "Robert "].map(name => name.trim()));

answered Nov 13, 2020 at 14:08

jenson-button-event

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Sarun UK · Accepted Answer · 2020-11-13 14:12:30Z

1

 function cleanNames(input) {
   return input.map(val => val.trim());
}
const names = [" Joy ", " James", "Raj"];
console.log(cleanNames(names));

edited Nov 13, 2020 at 14:12

answered Nov 13, 2020 at 14:06

Sarun UK

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ransh · Accepted Answer · 2020-11-13 14:17:34Z

0

You should try and make the minimum amount of code:

[' aa ', ' b b ', '   c c '].map(i=>i.trim());

This will solve your problem.

By the way, if you are using jQuery the syntax is a bit different and even simpler:

$.map([' aa ', ' bb ', '   cc '], $.trim);

answered Nov 13, 2020 at 14:17

ransh

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