PHP misses system variables when using exec

Question

So i have a project where I send spotify track URL to server and store it. I use laragon with PHP 7.4 installed, windows 11. I use that downloader. It works via cmd command line. When I try to use it by hand it works fine, but when i send it by exec() it doesn't work. I can't get any return message neither. I have tried using exec(), system() and shell_exec() functions. The problem might be with with system variables, as these might not be visible for PHP. I have also tried turning on/off server and it didn't work. I have also tried to put putenv('PATH=' . $_SERVER['PATH']) at the beginning of file. I tried to check laragon path variables itself - I couldn't see these i have added. Any other default windows commands works as should be. Any ideas on how to fix it?

Here is my PHP code:

function createFile($url, $token){

    function execCommand($dir, $url){
        $command1 = "cd $dir";
        $command2 = "spotdl $url";
        if(!shell_exec($command1. "&& ". $command2)) return false;
        return true;
    }

    $path = "C:\Laragon/laragon/www/temp/";  
    $dir = $path.$token.'/';
    if(!mkdir($dir, 0777)) throwError("Server error");
    if(!execCommand($dir, $url)) return false;
    return true;
}

I know i'm not returning any output from console, but that is post updates. Second command is definitely beeing called, i have tested it on some other commands (like mkdir)

Can you pass the code example ?

Gytree
– Gytree

2022-01-22 17:14:56 +00:00
Commented Jan 22, 2022 at 17:14 — Gytree
– Gytree, Commented Jan 22, 2022 at 17:14
@Gytree Yes, I have edited question

Dominik Śliwiński
– Dominik Śliwiński

2022-01-22 17:27:18 +00:00
Commented Jan 22, 2022 at 17:27 — Dominik Śliwiński
– Dominik Śliwiński, Commented Jan 22, 2022 at 17:27

Gytree · Accepted Answer · 2022-01-22 17:43:05Z

1

In many os the errors output (stderr) of the commands isn't the same that the normal output (stdout), you need to redirect the errors to the stdout. so the command must be:

$ command $arg1 $arg2 ... 2>&1

This cause that the errors messages will be sent to the stdout, Is util remember this when you are working with system calls.

Now in your code i prefer to use the exec function in php

<?php
$result = 0;
$output = [];
$command = "your command with the 2>&1";
exec($command, $output, $result);
if ($result != 0) {
    // here an error ocurred and you can see the error on the ouput array
    exit();
}
// here you know that the command was executed successfully

answered Jan 22, 2022 at 17:43

Gytree

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6 Comments

Dominik Śliwiński Over a year ago

I have refactored code and i got output: array(2) { [0]=> string(62) "'spotdl' is not recognized as an internal or external command," [1]=> string(31) "operable program or batch file." } And as i said - spotdl is working fine on cmd run by hand.

Gytree Over a year ago

How you install the spotdl?

Dominik Śliwiński Over a year ago

Followed official git guide given here

Gytree Over a year ago

maybe is an issue with the laragon and the path.

Dominik Śliwiński Over a year ago

Okay, so i have found a solution: After re-installing laragon it worked. I Have checked before uninstalling path variables and i haven't seen mine that should be in. I couldn't modify it either so I just reinstalled it.

|

Elikill58 · Accepted Answer · 2022-01-23 13:50:04Z

0

After re-installing laragon it worked. I Have checked before uninstalling path variables and i haven't seen mine that should be in.

I couldn't modify it either so I just reinstalled it.

edited Jan 23, 2022 at 13:50

Elikill58

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answered Jan 23, 2022 at 10:07

Dominik Śliwiński

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