FileInputStream without Creating an Actual File using Java

Question

I was wondering if there was any way to create a FileInputStream object from just a file object without creating an actual file on the file system? What I am attempting to do is create a file object with some information, and then upload that file somewhere else. I have no need for it to be on the local file system. I know that I could just create a temp folder and then delete it afterwards, but was wondering if it was possible to not do it that way?

You could use tmpfs on Unix or a ramdisk on Windows. A ByteArrayInputStream is likely to be the simplest. — Peter Lawrey
– Peter Lawrey, Commented Jan 10, 2012 at 13:36

Michael Borgwardt · Accepted Answer · 2012-01-10 13:37:23Z

5

What I am attempting to do is create a file object with some information, and then upload that file somewhere else

In that case you should not work with any file-related classes at all. Instead, crate a byte array, which you can tread as an InputStream via ByteArrayInputStream.

answered Jan 10, 2012 at 13:37

Michael Borgwardt

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Michael Piefel · Accepted Answer · 2012-01-10 13:34:57Z

5

You are probably looking for a ByteArrayInputStream or something similar.

A file input stream reads from a file on disk, that is its purpose. By the way, a File object in Java does not really represent a file, but rather the path pointing to a (potential) file on disk.

answered Jan 10, 2012 at 13:34

Michael Piefel

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4 Comments

Peter Lawrey Over a year ago

+1 You can use a ByteArrayOutputStream to help you build the data for the "file"

Reid Mac Over a year ago

I am having to call the following method which I cannot change, it's from the VersionOne API: createAttachment(String name, String fileName, InputStream stream) throws AttachmentLengthExceededException, ApplicationUnavailableException

Andrew Thompson Over a year ago

@ReidMac So what is the problems exactly?

Reid Mac Over a year ago

@AndrewThompson Nothing, just providing more information, sorry. Trying this now.

Adel Boutros · Accepted Answer · 2012-01-10 13:33:36Z

0

Try creating a memory stream, your file is stored in the memory instead of the file system

answered Jan 10, 2012 at 13:33

Adel Boutros

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