5

I was trying to put a nested if in algorithm area like this:

          \If{$isContentMethod(\mathcal{M})$}{
            $URI \leftarrow getURI(SubCG, \mathcal{M})$\;
            \If($URI \in \mathcal{P}_c$){
                $Permission \leftarrow getPermission(URI, \mathcal{P}_c)$\;
                $\mathcal{B}.add(Permission, URI, Entrypoints)$ \;
            }
         }

But LaTeX keep giving me errors:

! Argument of \algocf@Ifmain has an extra }.
<inserted text>
\par
l.69 }
I've run across a `}' that doesn't seem to match anything.
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  • Welcome to TeX.SX! Could you post a complete minimal working example? It is really of help to answer you. Commented Dec 6, 2013 at 19:27
  • Welcome to TeX.SX! Please make your code compilable (if possible), or at least complete it with \documentclass{...}, \begin{document}, and \end{document}. That may seem tedious to you, but think of the extra work it represents for TeX.SX users willing to give you a hand. Help them help you: remove that one hurdle between you and a solution to your problem. Commented Dec 6, 2013 at 19:49

1 Answer 1

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6

While algorithm2e does supply an \If(..)-style conditional (for commenting), you're probably after \If{..}{...} inside your nested if. The reason for the failure is because the \If(..)-style usage requires more arguments than you are currently supplying.

Mere's a MWE:

enter image description here

\documentclass{article}
\usepackage{algorithm2e}% http://ctan.org/pkg/algorithm2e
\begin{document} 
\begin{algorithm}
\If{$isContentMethod(\mathcal{M})$}{
  $URI \leftarrow getURI(SubCG, \mathcal{M})$\;
  \If{$URI \in \mathcal{P}_c$}{% Don't use `\If(..)`
    $Permission \leftarrow getPermission(URI, \mathcal{P}_c)$\;
    $\mathcal{B}.add(Permission, URI, Entrypoints)$ \;
  }
}
\end{algorithm}
\end{document}

Also consider using the amsmath package that provides \text{...} for setting some of your text-related math content.

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1
  • Thanks a lot! I made a mistake by using () instead of {} Commented Dec 6, 2013 at 19:32

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