how to keep running the script settings?

Question

I am writing a script called pickanumber.sh. I was setting up the script so I will ask the user to pick a number. If the number that they type is not "8" than the script will continue running. I can't make the script keep running when the user picks a number other than "8". Should I use for loop or while loop? Here is the script that I have so far.

rand_num=0
let "rand_num = $RANDOM % 10 + 1"
echo $rand_num
echo -n "pick a number from 1 - 10! "
read pickanumber
if [ "$pickanumber" = "8" ]; then
   echo "GOOD JOB"
else
   read $pickanumber
fi

Ipor Sircer · Accepted Answer · 2017-03-14 05:45:12Z

1

Use while loop, or until.

until [ "$pickanumber" = "8" ]; do
    echo -n "pick a number from 1 - 10! "
    read pickanumber
done
echo "GOOD JOB"

answered Mar 14, 2017 at 5:45

Ipor Sircer

14.9k2 gold badges31 silver badges44 bronze badges

thank you @ipor Siecer. it works. when i used until command. but when i try using while loop, it takes every number as a correct number. can you tell me how to use while loop in this case ? thank you.

jose R
– jose R

2017-03-14 05:55:08 +00:00
Commented Mar 14, 2017 at 5:55

Add a comment |

Kerkouch · Accepted Answer · 2017-03-14 06:03:23Z

0

#!/bin/bash
let "rand_num = $RANDOM % 10 +1"
pickanumber=0
printf "Pick a number on this range [1-10]:"
read pickanumber

while [ true ]; do
 if [ $pickanumber -eq $rand_num ];then
  echo "Good Job!"
  exit
 else
  printf "Wrong, try again?"
  read pickanumber
 fi
done

answered Mar 14, 2017 at 6:03

Kerkouch

1864 bronze badges

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