I have a file with below lines
This is an PLUTO
This is PINEAPPLE
This is ORANGE
This is RICE
How do I make a new line above each lines and insert the last string to the new line output as below:
PLUTO:
This is an PLUTO
PINEAPPLE:
This is an PINEAPPLE
ORANGE:
This is an ORANGE
RICE:
This is an RICE
Thanks
Using awk to print the last field of each line followed by a colon before printing the line itself:
$ awk '{ print $NF ":"; print }' file
PLUTO:
This is an PLUTO
PINEAPPLE:
This is PINEAPPLE
ORANGE:
This is ORANGE
RICE:
This is RICE
Variation that uses a single print statement but that explicitly prints the output record separator (a newline) and $0 (the line):
awk '{ print $NF ":" ORS $0 }' file
Variation using printf instead:
awk '{ printf("%s:\n%s\n", $NF, $0) }' file
Using sed:
$ sed 'h; s/.* //; s/$/:/; G' file
PLUTO:
This is an PLUTO
PINEAPPLE:
This is PINEAPPLE
ORANGE:
This is ORANGE
RICE:
This is RICE
Annotated sed script:
h; # Copy the pattern space (the current line) into the hold space (general purpose buffer)
s/.* //; # Remove everything up to the last space character in the pattern space
s/$/:/; # Add colon at the end
G; # Append the hold space (original line) with an embedded newline character
# (implicit print)
s/// command, no hold copy, portable way to add a newline sed solution: sed 'G; s/\(.*\) \(.*\)\(\n\)$/\2:\3\1 \2/' inf1
sed code appears to require at least one space on the line to be able to insert the colon.
sed -E 'G;s/(.*)(\b[^ ]+)(\n)/\2:\3\1\2/' file.
Try this awk
awk '{$0=$NF":\n"$0}1' file
