I want to show the image only if there is info in the field. And the link around the image uses the info in the field. The mailto: field is coming up blank. So I'm guessing/hoping I'm doing something wrong with the way I'm printing/calling it. I would greatly appreciate any help.
<?php $email = types_render_field ("email");
if ( $email ) { ?>
<a href="mailto:<?php $email ?>"><img src="<?php bloginfo( 'template_url' ); ?>/images/icon-email.gif" width="24" height="24" /></a>
<?php } ?>
In case it's relevant, I'm using the Types plugin to create my custom fields.