Java: Can not load a properties file. Why?

Question

I am trying to load a properties file.
I have the properties file in the same directory as the class that I am trying to load it.
Example:

package com.classes.internal;   
public class ClassA {  

    private static String PFILE = "config.properties";  


    private static void methodA(){  
    //do stuff  
        Properties properties = null;  
        try{  
            properties = new Properties();  
            properties.load(new FileInputStream(PFILE));  
            //properties.load(new ClassA().getClass().getResourceAsStream(PFILE)); --> Does not work either   

        }catch(Exception e){  
            e.printStackTrace();  
        }  


    }

Also config.properties file is in com\classes\internal dir

But I get a FileNotFoundException or java.lang.NullPointerException (if using the commented out line instead of the first)

What am I doing wrong here? What am I missunderstanding?

Where is properties file relative to your classpath ?

Jigar Joshi
– Jigar Joshi

2012-04-06 07:08:20 +00:00
Commented Apr 6, 2012 at 7:08 — Jigar Joshi
– Jigar Joshi, Commented Apr 6, 2012 at 7:08
It is in the same directory as ClassA

Jim
– Jim

2012-04-06 07:11:21 +00:00
Commented Apr 6, 2012 at 7:11 — Jim
– Jim, Commented Apr 6, 2012 at 7:11
Similar question: stackoverflow.com/questions/7688710/…

Sorin
– Sorin

2012-04-06 07:12:37 +00:00
Commented Apr 6, 2012 at 7:12 — Sorin
– Sorin, Commented Apr 6, 2012 at 7:12

FrankieTheKneeMan · Accepted Answer · 2012-04-06 07:10:59Z

2

The file needs to be in the directory you're executing from, not the directory where the class file is.

So if you have the directory structure

Project/com/classes/internal

and you run the command

Project$ java com.classes.internal.SomeClass

Your JVM will look for the "config.properties" file in the "Project" directory.

answered Apr 6, 2012 at 7:10

FrankieTheKneeMan

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2 Comments

Jim Over a year ago

I am not sure I understand this.But then what is the meaning of getClass().getResourceAsStream etc?

mtk Over a year ago

getClass().getResourceAsStream is looking for the file in the folder where the source file for the current class is stored. Try doing System.out.println(new ClassA().getClass().getResourceAsStream("config.properties")); by placing the config.properties file in the folder as stated before.

ice · Accepted Answer · 2012-04-06 07:11:26Z

0

I think your program work directory not in com\classes\internal. Try to pass this relative path:

com\classes\internal\config.properties

or absolute path. You can obtain current working directory like this

String currentDir = new File(".").getAbsolutePath();

answered Apr 6, 2012 at 7:11

ice

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Comments

Andrew Thompson · Accepted Answer · 2012-04-06 07:20:08Z

0

properties.load(this.getClass().getResourceAsStream(
    "/com/classes/internal/" + PFILE));

answered Apr 6, 2012 at 7:20

Andrew Thompson

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2 Comments

Jim Over a year ago

There is no this.I am in a static method

Andrew Thompson Over a year ago

..and what happened when you used the earlier form, with the altered location string? Note that I'm not in the mood for playing '20 questions' - it pays to use a little initiative when offered answers.

ThiamTeck · Accepted Answer · 2012-04-06 07:50:24Z

0

The line below will load file relative to working directory (in FrankieTheKneeMan example, the "Project" folder. If you are running your code in Tomcat, it is quite likely from $Tomcat/bin/):

properties.load(new FileInputStream(PFILE));

And for the line below, it is loading file relative to your classpath. So "config.properties" refer to directory that contain your "com" folder, instead of "com/classes/internal/".

properties.load(new ClassA().getClass().getResourceAsStream(PFILE));

So you need to decide on whether to load from classpath, or from working directory.

answered Apr 6, 2012 at 7:50

ThiamTeck

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Comments

viktor · Accepted Answer · 2012-04-06 08:06:31Z

0

Example. I'm using eclipse project structure, I hope you get the picture anyway:

//File in Project/src/com/classes/internal/config.properties
InputStream in = ClassA.class.getResourceAsStream("config.properties");
Properties p = new Properties();
try {
   p.load(in);
} catch(IOException e) {
   e.printStackTrace();
}

In case you decide to put your file outside package:

//File in Project/src/config.properties
InputStream in = ClassA.class.getClassLoader().getResourceAsStream("config.properties");

Note that getResourceAsStream file has to be included in your classpath.

answered Apr 6, 2012 at 8:06

viktor

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Comments

Ajay Kelkar · Accepted Answer · 2014-10-14 06:29:11Z

0

Create a config package in the source folder directly and place the config.properties file in it. On building the application, it will go to /WEB-INF/classes/config/config.properties

You can then use the following code to access the properties file -

    Properties prop = new Properties();
    String propFileName = "/config/config.properties";

    InputStream input = null;

    input = ClassA.class.getResourceAsStream(propFileName);
    prop.load(input);

answered Oct 14, 2014 at 6:29

Ajay Kelkar

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