<font size="+1"><font size="+2" color="green"><b>1.</b>
</font><b>If no head injury is too trivial to be neglected, then:</b></font>
In PHP using preg_match or preg_match_all I want to retrieve the text "If no head injury is too trivial to be neglected, then:"
How can I do this?
Code :
<?php
$str = '<font size="+1"><font size="+2" color="green"><b>1.</b></font><b>If no head injury is too trivial to be neglected, then:</b></font>';
$pattern = "/font><b>(.+)<\/b>/";
preg_match($pattern,$str,$matches);
echo $matches[1];
?>
Output :
If no head injury is too trivial to be neglected, then:
I am not sure, under what conditiones you select the string to capture, why gets 1. not captured, but your 2. string does? As long, as you do not explain that I can only guess, so as an expression:
/<\w+(?:\s+\w+=(?:(?:"[^"]*")|(?:'[^']*')))*\s*>([^<]+)</\w+>/g
will match all html tags, that only contain a text node (wich should be case for xhtml, since <p>text<br /></p> would not be wellformed...).
so <p>text</p><br>text2</br> will be matched and as a result the text will be in capturegroup 1.
<\w+(?:\s+\w+=(?:(?:"[^"]*")|(?:'[^']*')))*\s*> will capture every opening xhtml tag
([^<]+) will catch all cahrs exept from < and put it in the capturegroup
</\w+> finally catches the closing tag...
the g is the global flag so that the expression can catch multiple results...
Good luck with this, if you need something different please be a little more precise...
The pattern will be something like this:
/<\s*b\s*>(.+)<\s*\/b\s*>/
