php call private variable inside another private variable error

Question

My PHP Code:

<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');

class admin extends CI_Controller {

    function __construct(){
        parent::__construct();
        $this->load->helper('ajax');
    }

    private $password = 'password';

    private $login_details = array(
        'username' => 'username',
        'password' => sha1('salt'.$this->password)
    );

the above code returns the following PHP error:

Parse error: syntax error, unexpected '(', expecting ')'

i am using codeigniter but i dont think that this has something to do with the problem since its PHP based...

@safarov i know that, i cant see how to fix it...

stergosz
– stergosz

2012-04-07 18:14:38 +00:00
Commented Apr 7, 2012 at 18:14 — stergosz
– stergosz, Commented Apr 7, 2012 at 18:14

Marc B · Accepted Answer · 2012-04-07 18:15:06Z

2

Class members have to be initialized with static values. You can't use a function result in the initialization, so

    'password' => sha1('salt'.$this->password)

is forbidden. You'll have to do that in the constructor instead.

answered Apr 7, 2012 at 18:15

Marc B

362k44 gold badges433 silver badges508 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

php call private variable inside another private variable error

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related