Parse a number from a string

Question

i have string like those / 5 or / 91 or / 358. I need to get the integers after last space from those strings. Here is how I do it know but it only can get one number. How to make it?

f_quantity = f_quantity.substr(f_quantity.length - 1);

try parseInt or parseFloat

SpYk3HH
– SpYk3HH

2012-04-10 14:44:02 +00:00
Commented Apr 10, 2012 at 14:44 — SpYk3HH
– SpYk3HH, Commented Apr 10, 2012 at 14:44
@karim79 There is space before / too :P

Selvakumar Arumugam
– Selvakumar Arumugam

2012-04-10 14:45:29 +00:00
Commented Apr 10, 2012 at 14:45 — Selvakumar Arumugam
– Selvakumar Arumugam, Commented Apr 10, 2012 at 14:45
parseInt(f_quantity.split("/")[1],10) then

Tei
– Tei

2012-04-10 15:16:43 +00:00
Commented Apr 10, 2012 at 15:16 — Tei
– Tei, Commented Apr 10, 2012 at 15:16

Marc · Accepted Answer · 2012-04-10 14:49:43Z

3

Simple example you can validate in a web console:

console.log( (' / 358').match("[0-9]+") );

So...

f_quantity = (' / 358').match("[0-9]+");

answered Apr 10, 2012 at 14:49

Marc

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Comments

levi · Accepted Answer · 2012-04-10 14:47:04Z

0

if there is space before the last number you can write the following:

string val = ' / 5' or ' / 91' or ' / 358'. 
var arr = val.split(' ');
arr[val.length-1];

answered Apr 10, 2012 at 14:47

levi

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Comments

talnicolas · Accepted Answer · 2012-04-10 14:47:43Z

0

You could use something like this that will get you the number:

var s = " / 91";
var pattern = /[0-9]+/;
var num = s.match(pattern);

answered Apr 10, 2012 at 14:47

talnicolas

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Comments

David Downes · Accepted Answer · 2012-04-10 14:48:02Z

0

Is the string always of the format ' / NUM'? If so, use this to get the string of the number:

f_quantity = f_quantity.substr(3, f_quantity.length);

And then this to turn it into an actual number:

f_quantity = parseInt(f_quantity);

Or as a one-liner:

f_quantity = parseInt(f_quantity.substr(3, f_quantity.length));

answered Apr 10, 2012 at 14:48

David Downes

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Comments

Robert Messerle · Accepted Answer · 2012-04-10 14:58:55Z

0

This will give you the last integer value preceded by a space, allowing for additional white space at the end:

f_quantity = ~~f_quantity.match( /\s+\d+\s*$/ )

edited Apr 10, 2012 at 14:58

answered Apr 10, 2012 at 14:50

Robert Messerle

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