Windows batch programing check passed argument value

Question

I am trying with windows batch command. not Getting the result as expected.

i am passing 4 args to a batch file and inside the batch file i am checking if the 4th arg value is "1"

here the code snippet.

IF %%4=="1" (
echo "Error Level is zero"
echo 'Creating web Ears...'
set cd=%CD%
echo "Current Directory: " %cd%
)

Even after passing the exact value 1, if condition doesn't evaluate to true. Can someone please identify in mistake?

mybat.bat x 5 c 1

Instead of using bat batch files, take a look at power shell - it is much more powerful. — Oded
– Oded, Commented Apr 15, 2012 at 18:44

CharlesB · Accepted Answer · 2012-04-15 18:55:57Z

2

Found two errors:

Use just one %
Remove the double quote around 1

IF %4==1 (  
echo "Error Level is zero"  
echo 'Creating web Ears...'  
set cd=%CD%  
echo "Current Directory: " %cd%  
)

Tested by Command Prompt on Win7 64bit

edited Apr 15, 2012 at 18:55

CharlesB

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answered Apr 15, 2012 at 18:51

Steve

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1 Comment

Andriy M Over a year ago

If the fourth parameter is empty, the IF statement will break with a message about syntax error. It would be safer to add characters to both sides of the comparison (typically quotation marks, but that isn't a fixed rule, of course), something like this: IF "%4" == "1" (….

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