I have used this function to submit to any url or 'self', with or without a querystring, many times without any problems.
function submitu(url, q) {
var frm = document.<?php echo $formname ?>;
if (url == '') {url = '<?php echo $thispage?>'; }
frm.action = url+q; frm.submit(); }
If I try to move the PHP vars outside the function, as below, it stops working (frm undefined error)
var thispage = '<?php echo $thispage?>';
var frm = document.<?php echo $formname?>;
function submitu(url, q) {
if (url == '') {url = thispage;}
frm.action = url+q; frm.submit();}
I also tried var frm = document.forms[''];
I don't have any other conflicting javascript,
(1). Can anyone tell me why this is not working? (2). And why the first method also fails if the function is placed inside and at the top of the jquery $(function() {.....} ready function?
Many thanks