PHP echo variable not appearing correctly

Question

I have the following

 <?php echo '<img src="/wp-content/themes/CAFC/images/cards/big/'.get_post_meta($post->ID, "bigcard", true).'" alt="'.the_title().'" />'; ?>

For some reason however my 'the_title' variable is appearing before my image when outputted as so...

UK Fuels Fuel Card
<img alt="" src="/wp-content/themes/CAFC/images/cards/big/ukfuels.png">

Can anybody give me an idea of where im going wrong?

Oops. Deleted my comment. Anyway, try using the standard "View source" rather than Firebug. Should show up correctly. — Michael
– Michael, Commented Apr 19, 2012 at 17:34
Also, I misunderstood your problem. Thought you were asking why "alt" was before "src". — Michael
– Michael, Commented Apr 19, 2012 at 17:35

jeremyharris · Accepted Answer · 2012-04-19 17:33:15Z

5

This is because the_title() auto echoes the title. Try get_the_title() instead.

answered Apr 19, 2012 at 17:33

jeremyharris

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1 Comment

jeremyharris Over a year ago

If it's WordPress, you can pretty much assume it will auto echo. This is to make things "easy" I suppose. #dumb

Justin Howard · Accepted Answer · 2016-03-15 00:01:19Z

1

Try to use as:

$title = the_title();

and, use this $title in place of the_title();

edited Mar 15, 2016 at 0:01

Justin Howard

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answered Apr 19, 2012 at 17:39

Waheed Ur Rehman

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Comments

Vipin Jain · Accepted Answer · 2012-04-19 17:35:50Z

0

Use this instead:

<?php echo '<img src="/wp-content/themes/CAFC/images/cards/big/'.get_post_meta($post->ID, "bigcard", true).'" alt="'.get_the_title().'" />'; ?>

answered Apr 19, 2012 at 17:35

Vipin Jain

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Radek · Accepted Answer · 2012-04-19 17:36:38Z

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I think it's your browser. It changes the position of attributes for you. F. ex. Firefox can fix some HTML code according to standard.

answered Apr 19, 2012 at 17:36

Radek

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