How do I grep this pattern with regular-expression in shell?

Question

I want to grep the pattern like "1-10","10-20","1-9"(without double quotes) with the following code:

grep '[[:digit:]]\-[[:digit:]]' mydoc

It is ok to grep "1-9" but I can't figure out how to grep other two patterns!

user unknown · Accepted Answer · 2012-04-22 17:08:44Z

2

The minus needs no masking. + allows multiple occurrences.

egrep '[0-9]+-[0-9]+' mydoc

answered Apr 22, 2012 at 17:08

user unknown

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Comments

mkjeldsen · Accepted Answer · 2012-04-22 19:06:47Z

1

grep -E '[[:digit:]]+-[[:digit:]]+' mydoc

grep -E '[[:digit:]]{1,2}-[[:digit:]]{1,2}' mydoc

?

answered Apr 22, 2012 at 13:36

mkjeldsen

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afaik, the '-' needs no masking.