PHP, How would I load different content for a page depending on a url variable?

Question

For example:

if I just have cite.php, it would default to something

if it is cite.php?c=1, then it would load other content.

same as cite.php?c=2 ....etc

I did it before using a switch,case statement but I forgot how to do it :(

mgraph · Accepted Answer · 2012-04-23 23:38:16Z

3

$f = $_GET["c"];

switch($f){
  case 1:
    /* content here*/
  break;

  case 2:
  /* content here*/
  break;
}

answered Apr 23, 2012 at 23:38

mgraph

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1 Comment

dwurf Over a year ago

What happens if $f is null? :)

Fazle Elahee · Accepted Answer · 2012-04-23 23:42:17Z

1

You may use this code:

        $c = isset($_GET['c'])?$_GET['c'] : ''; 
    switch ($c) {

    case 1:
        /* Do something related to 1 */
        break;
    case 2:
        /* Do something related to 2 */
        break;
    default:
      /* Do something related to default */
    }

answered Apr 23, 2012 at 23:42

Fazle Elahee

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Comments

Tom · Accepted Answer · 2012-04-23 23:36:27Z

0

You can use the &_GET variable:

<?php echo $_GET["c"]; ?>

answered Apr 23, 2012 at 23:36

Tom

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Paul Dessert · Accepted Answer · 2012-04-23 23:36:56Z

0

you'll use $_GET[]

if isset($_GET['c']) {
    /* write code to show specific info *?
} else {
    /* show other info here */
}

answered Apr 23, 2012 at 23:36

Paul Dessert

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Comments

Raphael1 · Accepted Answer · 2012-04-24 00:26:45Z

0

you can do this much simpler with if statements

place this code in the header page

<?php 

$page = $_GET['c'];

if(!isset($page)) {
    header('location:cite.php?c=1');
    exit;
}

?>

then use this to load display different element on the page(place between <body></body> tags)

<? if ($page == "1") {?>

<h2>page 1</h2>

<? } else if ($page == "2") { ?>
<h2>page 2</h2>


<? } ?>

and the links will look like this

<a herf="cite.php?c=1">Link 1</a> <a herf="cite.php?c=2">Link 2</a>

answered Apr 24, 2012 at 0:26

Raphael1

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