output specific array key for each result

Question

i have a search engine for my page. as a result i would like to ouput the array key for each result.

so i have this code:

$results = search($keywords);
$results_num = count($results); //what shows the message how many items were found

if (!empty($errors){
foreach ($results as $result){
    echo "this is result: "
.$result['key'];       //thought would be the solution, its not.
    }
} else {
    foreach ($errors as $error){
        $error;
    }
}

i also tried using a counter like:

$results = search($keywords);
$results_num = count($results); //what shows the message how many items were found
$counter = 0;

if (!empty($errors){
foreach ($results as $result){
    $counter++;
    echo "this is result: "
.$counter;
    }
} else {
    foreach ($errors as $error){
        $error;
    }
}

what doesnt work as i thought and is still not that professional. so if there is someone who could tell me how to solve this i really would appreciate. thanks a lot.

to the part with the counter: it must be ++$counter; or $counter++; — user1150525
– user1150525, Commented Apr 24, 2012 at 9:38

billyonecan · Accepted Answer · 2012-04-24 10:31:43Z

2

foreach ($results as $key => $result) {
  echo 'this is result: ' . $key;
}

The current key will be assigned to $key and the value for that property will be assigned to $result

http://php.net/manual/en/control-structures.foreach.php

edit

In response to your comments, I think this is what you're trying to achieve:-

$i=0;
foreach($results as $result) {
  echo 'this is result: ' . ++$i;
}

edited Apr 24, 2012 at 10:31

answered Apr 24, 2012 at 9:40

billyonecan

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8 Comments

bonny Over a year ago

this works great. just one more thing i would like to know. how can i set the start at 1 and not 0? thanks a lot.

billyonecan Over a year ago

You could skip the first iteration of the array using continue, I'll edit my answer

bonny Over a year ago

is there still another way? the first array[0] contains input. in case of using that the input wont be displayed.

billyonecan Over a year ago

Sorry I wrongly assumed you had a numerically indexed array, not really sure why as it wouldn't have made sense. I've updated my answer.

bonny Over a year ago

i get the same mistake. it seems like continue easily jumps to the next entry in that array. so the first wont be considered.

|

web2students.com · Accepted Answer · 2012-04-24 09:40:14Z

1

foreach($arr as $key=>$val){
//do something with key and value
}

answered Apr 24, 2012 at 9:40

web2students.com

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Comments

Er. Anurag Jain · Accepted Answer · 2012-04-24 10:44:21Z

0

Here in code you can check first if $results array is not empty because sometime due to empty $results array foreach generates error

/*Check if $results array is empty or not*/
if(!empty($results)){  
 foreach ($results as $key=>$result){
  /*result you want to show here according conditions*/
 }
}

answered Apr 24, 2012 at 10:44

Er. Anurag Jain

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