How can i get the value of attribute in of a xml node in php?

Question

I'm using simplexml to read a xml file. So far i'm unable to get the attribute value i'm looking for. this is my code.

          if(file_exists($xmlfile)){
              $doc = new DOMDocument();
              $doc->load($xmlfile);
              $usergroup = $doc->getElementsByTagName( "preset" );
              foreach($usergroup as $group){         
                 $pname = $group->getElementsByTagName( "name" );
                 $att = 'code';
                 $name = $pname->attributes()->$att; //not working

                 $name = $pname->getAttribute('code'); //not working
                 if($name==$preset_name){
                     echo($name);
                      $group->parentNode->removeChild($group);
                 }
              }
          }

and my xml file looks like

<presets>
<preset>
 <name code="default">Default</name>
  <createdBy>named</createdBy>
  <icons>somethignhere</icons>
 </preset>
</presets>

Dr.Kameleon · Accepted Answer · 2012-04-27 09:58:55Z

3

Try this :

function getByPattern($pattern, $source)
{
    $dom = new DOMDocument();
    @$dom->loadHTML($source);

    $xpath = new DOMXPath($dom);
    $result = $xpath->evaluate($pattern);

    return $result;
}

And you may use it like (using XPath) :

$data = getByPattern("/regions/testclass1/presets/preset",$xml);

UPDATE

Code :

<?php
    $xmlstr = "<?xml version=\"1.0\" encoding=\"UTF-8\" ?><presets><preset><name code=\"default\">Default</name><createdBy>named</createdBy><icons>somethignhere</icons></preset></presets>";

    $xml = new SimpleXMLElement($xmlstr);

    $result = $xml->xpath("/presets/preset/name");

    foreach($result[0]->attributes() as $a => $b) {
        echo $a,'="',$b,"\"\n";
    }

?>

Output :

code="default"

P.S. And also try accepting answers as @TJHeuvel mentioned; it's an indication that you respect the community (and the community will be more than happy to help you more, next time...)

edited Apr 27, 2012 at 9:58

answered Apr 27, 2012 at 9:01

Dr.Kameleon

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22 Comments

guitarlass Over a year ago

thanks i dont understand how to get the attribute value from your code. And i have posted a wrong xml code please check the edit.

Dr.Kameleon Over a year ago

@guitarlass What is it that you don't understand? Just copy-paste the function I sent you, and use it as I've shown you (to get a specific element). if you want to get /presets/preset/name (= the full path to your element), then use it like $data = getByPattern("/presets/preset/name",$xml). Simple as that. :-)

guitarlass Over a year ago

yes i undertand that but, how can i get the attribute code 's value ?

Dr.Kameleon Over a year ago

@guitarlass if you have the element stored in $data, then to get the code attribute, just try : $data->getAttribute("code").

guitarlass Over a year ago

ok thanks but why doesn't my code working? i have coded $name = $pname->getAttribute('code');

|

guitarlass · Accepted Answer · 2012-04-30 01:49:58Z

Actually question in my head includes deleting a node as well , mistakenly i could not add it. So in my point of view this is the complete answer, i a case if someone else find this useful. This answer doesn't include SimpleXMLElement class because how hard i tried it didn't delete the node with unset(); . So back to where i was , i finally found an answer. This is my code. and its Simple!!!

if(file_exists($xmlfile)){
              $doc = new DOMDocument();
              $doc->load($xmlfile);
              $presetgroup = $doc->getElementsByTagName( "preset" );
              foreach($presetgroup as $group){       
                 $pname = $group->getElementsByTagName( "name" );
                  $pcode = $pname->item(0)->getAttribute('code');
                 if($pcode==$preset_name){
                      echo($preset_name);
                      $group->parentNode->removeChild($group);
                 }
              }
          }
        $doc->save($xmlfile);

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