Why does the following code throw ArrayStoreException?
double[] a = {2.0,3.4,3.6,2.7,5.6};
int[] b = {2,3,4,5};
System.arraycopy(b,0,a,1,4);
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8If you claim that your code throws an exception, then you should at least post code that compiles.Joachim Sauer– Joachim Sauer2009-06-24 13:59:12 +00:00Commented Jun 24, 2009 at 13:59
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+1. someone edit that to at least say double[] a and int[] bGandalf– Gandalf2009-06-24 15:32:07 +00:00Commented Jun 24, 2009 at 15:32
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Now that the question is properly formatted and worded, please remove your downvotes.Robert Munteanu– Robert Munteanu2009-06-24 15:57:09 +00:00Commented Jun 24, 2009 at 15:57
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4 Answers
From the docs for System.arraycopy:
Otherwise, if any of the following is true, an ArrayStoreException is thrown and the destination is not modified:
[...]
The src argument and dest argument refer to arrays whose component types are different primitive types.
That's exactly the case here - int and double are different primitive types, so the exception is thrown as documented.
The point of arraycopy is that it can work blindingly fast by copying the raw data blindly, without having to apply any conversions. In your case it would have to apply conversions, so it fails.
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Yeah, that's the documented behavior for an arraycopy between arrays with different primitive types as components. Whether the type could normally be promoted isn't relevant; this is what arraycopy is designed to do.
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try double**[]** a = {2.0,3.4,3.6,2.7,5.6}; and int**[]** b
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There is no automatic conversion between int and double elements in the array with arraycopy(). The native method checks for array type equivalence and throws the ArrayStoreException on mismatch. You'll have to revert to the plain or method of looping:
for (int i = 0; i < a.length(); i++)
a[i] = b[i];
