Populate asp.net dropdownlist with number

Question

A simple query , i want to populate the dropdownlist with number starting from 17 to 90 , and the last number should be a string like 90+ instead of 90. I guess the logic will be using a for loop something like:

for (int a = 17; a <= 90; a++)
        {
            ddlAge.Items.Add(a.ToString());
        }

Also I want to populate the text and value of each list item with the same numbers. Any ideas?

Tim Schmelter · Accepted Answer · 2012-05-04 14:27:04Z

7

for (int i = 17; i < 90; i++)
{
    ddlAge.Items.Add(new ListItem(i.ToString(), i.ToString()));
}
ddlAge.Items.Add(new ListItem("90+", "90"));

answered May 4, 2012 at 14:27

Tim Schmelter

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Comments

James Johnson · Accepted Answer · 2012-05-04 14:27:30Z

5

Try this:

for (int a = 17; a <= 90; a++)
{
    var i = (a == 90 ? a.ToString() + '+': a.ToString());
    ddlAge.Items.Add(new ListItem(i, i));
}

edited May 4, 2012 at 14:27

James Johnson

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answered May 4, 2012 at 14:25

rs.

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3 Comments

Tim Schmelter Over a year ago

I don't want to be pedantic all the more on a competitive answer, but if i know that the only exception is the last item, why should i put the logic in the for loop at all? Simply add the exceptional item outside of the loop. That makes it also clearer.

Mr A Over a year ago

i agree with @TimSchmelter , y check all the numbers .

rs. Over a year ago

@TimSchmelter you are correct, you answered it, so I'll leave mine AS IS.

David East · Accepted Answer · 2012-05-04 14:26:39Z

3

This is easy enough. You need to instantiate the ListItem class and populate its properties and then add it to your DropDownList.

    private void GenerateNumbers()
    {
        // This would create 1 - 10
        for (int i = 1; i < 11; i++)
        {
            ListItem li = new ListItem();
            li.Text = i.ToString();
            li.Value = i.ToString();
            ddlAge.Items.Add(li);
        }
    }

answered May 4, 2012 at 14:26

David East

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1 Comment

James Johnson Over a year ago

This only answers part of the question. OP wants the last item to show as 90+ instead of just 90

Skorpioh · Accepted Answer · 2012-05-04 14:24:48Z

2

for (int a = 17; a <= 90; a++)
{
    ddlAge.Items.Add(new ListItem(a.ToString(), a.ToString()));
}

answered May 4, 2012 at 14:24

Skorpioh

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3 Comments

Mr A Over a year ago

why you passing the number 2 times

James Johnson Over a year ago

It's setting the text and value.

Tim Schmelter Over a year ago

You've forgotten to add 90+ as last item ;)

Enes Taha Selek · Accepted Answer · 2013-12-12 13:14:09Z

2

for (int i = 17; i <= 90; i++)
{
    ddlAge.Items.Add(new ListItem(i.ToString(), i.ToString()));
}
ddlAge.Items.Insert(0, new ListItem("Select Age", "0")); //First Item
ddlAge.Items.Insert(ddlAge.Items.Count, new ListItem("90+", "90+")); //Last Item

answered Dec 12, 2013 at 13:14

Enes Taha Selek

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Comments

Dilip Meghwal · Accepted Answer · 2013-07-01 16:48:37Z

0

for (int i = 0; i <=91; i++)
    {
        if (i == 0)
        {
            ddlAge.Items.Add("Select Age");
        }
        else if(i<=90)
        {
            ddlAge.Items.Add(i.ToString());
            i++;
        }
        else
        {
         ddlAge.Items.Add("90+");
        }
    }

answered Jul 1, 2013 at 16:48

Dilip Meghwal

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