Copying part of char array into new char array fails

Question

I want to copy a part of char array into a new one

void match(char* probe, char* pattern)
char* matchText;
//the char-array probe in this example is at least 12 characters long
//I'm only writing numbers in the strncopy-command to make it easier to understand
strncpy (matchText, probe + 5, 5 );

Upon running that the debugger quits with an error. What am I doing wrong?

What error is it? Are the arrays properly allocated?

Imp
– Imp

2012-05-08 17:32:46 +00:00
Commented May 8, 2012 at 17:32 — Imp
– Imp, Commented May 8, 2012 at 17:32

Alok Save · Accepted Answer · 2012-05-08 17:32:50Z

3

You need to allocate memory to matchText, what you have is just an pointer.
It must have enough memory allocated using malloc(since it is a pointer) to hold the string being copied in to it, or what you get is Undefined Behavior.

answered May 8, 2012 at 17:32

Alok Save

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