size_t convert/cast to string in C++ [duplicate]

Question

Possible Duplicate:
How to convert a number to string and vice versa in C++

How do I convert an integral value to a string in C++?

This is what I've tried:

for(size_t i = 0;vecServiceList.size()>i;i++)
{
    if ( ! vecServiceList[i].empty() )
    {
        string sService = "\t" + i +". "+  vecServiceList[i] ;
    }
}

And here is the error:

invalid operands of types 'const char*' and 'const char [3]' to binary 'operator+'

my first guess is that you need something, e.g. boost:format("%lu") % i, but what was the error? — guinny
– guinny, Commented May 9, 2012 at 5:00
@7heo.tk I don't see what that has to do with things /at all/. Also, the marked duplicate mentions all integral types perfectly fine, so that's not a problem. — sehe
– sehe, Commented Jul 5, 2016 at 14:46
@sehe my bad, I found this question searching for size_t safe alternative to atoi. I didn't bother to check if the question was written with "to" or "from". — 7heo.tk
– 7heo.tk, Commented Jul 5, 2016 at 14:54

dreamlax · Accepted Answer · 2012-05-09 05:07:27Z

23

You could use a string stream:

#include <sstream>

...


for (size_t i = 0; ... ; ...)
{
    std::stringstream ss;

    ss << "\t" << i << vecServiceList[i];

    std::string sService = ss.str();

    // do what you want with sService
}

answered May 9, 2012 at 5:07

dreamlax

95.7k31 gold badges166 silver badges211 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

size_t convert/cast to string in C++ [duplicate]

1 Answer 1

Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Linked

Related