I would like to execute a method in a thread. The method has multiple arguments and expects return value. Can anyone help?
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Are you able to use .NET 4.0?Alex– Alex2012-05-10 13:21:41 +00:00Commented May 10, 2012 at 13:21
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stackoverflow.com/questions/1314155/… OR stackoverflow.com/questions/8860141/…Robar– Robar2012-05-10 13:23:13 +00:00Commented May 10, 2012 at 13:23
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2 Answers
Thread thread = new Thread(() =>
{
var result = YourMethod(param1, param2);
// process result here (does not invoked on your main thread)
});
If you need to return result to main thread, then consider using Task (C# 4) instead:
var task = new Task<ReturnValueType>(() => YourMethod(param1, param2));
task.Start();
// later you can get value by calling task.Result;
Or with previous version of C#
Func<Param1Type, Param2Type, ReturnValueType> func = YourMethod;
IAsyncResult ar = func.BeginInvoke(param1, param2, null, null);
ar.AsyncWaitHandle.WaitOne();
var result = func.EndInvoke(ar);
answered May 10, 2012 at 13:19
Sergey Berezovskiy
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1 Comment
Sergey Berezovskiy
@Servy just avoided in this case
Func<string, int, bool> func = SomeMethod;
AsyncCallback callback = ar => { bool retValue = func.EndInvoke(ar); DoSomethingWithTheValue(retValue };
func.BeginInvoke("hello", 42, callback, null);
...
bool SomeMethod(string param1, int param2) { ... }
1 Comment
Sergey Berezovskiy
In this case
DoSomethingWithTheValue will not be executed on main thread. Same result you can achieve simply by calling Thread thread = new Thread(() => DoSomething(YourMethod(param1, param2)))