Echo variable and HTML in PHP IF statement

Question

I have the following code, which works exactly as I expect it to:

<?php if ($a - $b < 1)
echo $text;
elseif ($a - $b >= 1)
echo $a - $b;
else
echo $a; ?>

However, now I also want to add a bit of HTML to the echo depending on the result of the IF statement.

<?php if ($a - $b < 1)
echo $text;
elseif ($a - $b >= 1)
echo $a - $b;
<input type="button" value="<?php echo $button_txt; ?>" id="button" class="button" />
else
echo $a;
<input type="button" value="<?php echo $button2_txt; ?>" id="button" class="button" /> ?>

When I do this, I get the following error: Parse error: syntax error, unexpected '<' on line 213 (line 213 is referring to the first <input> line in the code above).

Is there any way to include both the variables, and the HTML in the echo part of the IF statement?

Are the HTML <input> tags supposed to be part of the if/else chain? if so you'll also need {} or you'll get a syntax error at the else. — Michael Berkowski
– Michael Berkowski, Commented May 16, 2012 at 18:11

Samy Dindane · Accepted Answer · 2012-05-16 18:18:38Z

2

Edit: Better formatting

<?php if ($a - $b < 1): ?>
  <?php echo $text ?>
<?php elseif ($a - $b >= 1): ?>
  <?php echo $a - $b ?>
  <input type="button" value="<?php echo $button_txt ?>" id="button" class="button" />
<?php else: ?>
  <input type="button" value="<?php echo $button2_txt ?>" id="button" class="button" />
<?php endif ?>

edited May 16, 2012 at 18:18

answered May 16, 2012 at 18:09

Samy Dindane

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Comments

William Kinaan · Accepted Answer · 2012-05-16 18:09:22Z

0

try this

<?php if ($a - $b < 1)
echo $text;
elseif ($a - $b >= 1)
{
echo $a - $b;
?>
<input type="button" value="<?php echo $button_txt; ?>" id="button" class="button" />
<?php
else
 {
echo $a;
?>
<input type="button" value="<?php echo $button2_txt; ?>" id="button" class="button" />
<?php } ?>

answered May 16, 2012 at 18:09

William Kinaan

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Comments

SupremeDud · Accepted Answer · 2012-05-16 18:09:22Z

0

you need to echo your lines of html:

<?php if ($a - $b < 1)
echo $text;
elseif ($a - $b >= 1)
echo $a - $b;
echo "<input type=\"button\" value=\"$button_txt\" id=\"button\" class=\"button\" />";
else
echo $a;
echo "<input type=\"button\" value=\"$button2_txt\" id=\"button\" class=\"button\" /> ?>

answered May 16, 2012 at 18:09

SupremeDud

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Comments

Max · Accepted Answer · 2012-05-16 18:11:00Z

0

You need to close your php statements before you start a html code so your code should look something like this :

<?php if ($a - $b < 1)
echo $text;
elseif ($a - $b >= 1)
echo $a - $b;
?>
<input type="button" value="<?php echo $button_txt; ?>" id="button" class="button" />
<?php else
echo $a;
?>
<input type="button" value="<?php echo $button2_txt; ?>" id="button" class="button" /> ?>

answered May 16, 2012 at 18:11

Max

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Comments

soimon · Accepted Answer · 2012-05-16 18:20:10Z

PHP and HTML are different languages which get interpreted differently. <input type="button"> has no meaning inside PHP and is actually invalid. PHP code goes between <?php and ?> tags, HTML goes outside those tags or between quotes (making it a string).

A solution could be:

<?php

if ($a - $b < 1)
    echo $text;
elseif ($a - $b >= 1)
{
    echo $a - $b;
    echo '<input type="button" value="' . $button_txt . '" id="button" class="button" />';
}
else
{
    echo $a;
    echo '<input type="button" value="' . $button2_txt . '" id="button" class="button" />';
}

?>

Note that the actual HTML code is now between ' and ' since within PHP it is seen as regular text. Also, I added the brackets { and }: when an if is followed by multiple instructions, the brackets are needed to specify the beginning and ending of the instructions that belong to the if. The same applies for the else.

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