Converting String to double in java. Change format of printed double

Question

I am reading a following CSV file in java and

1191196800.681 - !AIVDM,1,1,,,13aG?N0rh20E6sjN1J=9d4<00000,0*1D

Here is my code to read this CSV file and convert the 1st column of the CSV file (which is a String) to a double

public class ReadCSV {

public static void main(String[] args) {

    try {
        BufferedReader CSVFile = new BufferedReader(new FileReader(
                "C:\\example.txt"));

        try {
            String dataRow = CSVFile.readLine();

            while (dataRow != null) {
                String[] dataarray = dataRow.split("-");

                String temp = dataarray[0];

                double i = Double.parseDouble(temp);

                System.out.println(temp);
                System.out.println(i);
                dataRow = CSVFile.readLine();

            }

        } catch (IOException e) {
            e.printStackTrace();
        }
    } catch (FileNotFoundException e) {
        e.printStackTrace();
    }

}

}

When I execute the code I get the following values

1191196800.681 
1.191196800681E9

Why is the value of variable "temp" and "i" not the same. What changes must I do in the code to get the following values:

1191196800.681 
1191196800.681

Thanks in advance.

Don't print it in the default scientific notation? Try printf/format. — Dave Newton
– Dave Newton, Commented May 19, 2012 at 14:41

Hakan Serce · Accepted Answer · 2012-05-19 14:49:04Z

7

temp and i are exactly the same, just the double value is formatted in scientific notation. You can format it differently if you like using DecimalFormat for instance.

edited May 19, 2012 at 14:49

answered May 19, 2012 at 14:42

Hakan Serce

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Comments

Ankit Saxena · Accepted Answer · 2012-05-19 15:03:36Z

1

Yups vizier is correct what you need to do is this:

public static void main(String[] args) throws Exception {
    // TODO Auto-generated method stub
    String dataRow = "1191196800.681";


        String[] dataarray = dataRow.split("-");

        String temp = dataarray[0];
        DecimalFormat df = new DecimalFormat("#.###");
        double i = Double.parseDouble(temp);

        System.out.println(temp);
        System.out.println(df.format(i));

}

answered May 19, 2012 at 15:03

Ankit Saxena

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Comments

richarbernal · Accepted Answer · 2012-05-19 14:52:50Z

0

The other result is in scientific notation, but is the same.

If you want change the representation you can use String.format("%.3f", i), which represents the number with 3 decimals

answered May 19, 2012 at 14:52

richarbernal

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