What is the most efficient way to replace one sequence of the bytes (eg 67 67 67) with some other sequence of the bytes (eg 90). The sequences can have different length.
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What did you try?Oded– Oded2012-05-22 13:00:17 +00:00Commented May 22, 2012 at 13:00
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2And what kind of NOT nice solutions you found?Renatas M.– Renatas M.2012-05-22 13:00:30 +00:00Commented May 22, 2012 at 13:00
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If you know they are letters, can't you make a string and use its replace method?Davio– Davio2012-05-22 13:07:24 +00:00Commented May 22, 2012 at 13:07
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From what I understand the question is how to replace one sequence of the bytes (eg 67 67 67) with some other sequence of the bytes (eg 90). The sequences can have different length. It's not about simple chars replacement.Marek Musielak– Marek Musielak2012-05-22 13:15:30 +00:00Commented May 22, 2012 at 13:15
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1 Answer
Here is a short app which does what you need:
static void Main(string[] args)
{
byte [] bArray = new byte[] {11, 67, 67, 67, 33, 34, 67, 67, 11, 33, 67, 67, 67, 67};
byte[] result = Replace(bArray, new byte[] {67, 67, 67}, new byte[] {90});
foreach (byte b in result)
{
Console.WriteLine(b);
}
}
private static byte [] Replace(byte[] input, byte[] pattern, byte[] replacement)
{
if (pattern.Length == 0)
{
return input;
}
List<byte> result = new List<byte>();
int i;
for (i = 0; i <= input.Length - pattern.Length; i++)
{
bool foundMatch = true;
for (int j = 0; j < pattern.Length; j++)
{
if (input[i + j] != pattern[j])
{
foundMatch = false;
break;
}
}
if (foundMatch)
{
result.AddRange(replacement);
i += pattern.Length - 1;
}
else
{
result.Add(input[i]);
}
}
for (; i < input.Length; i++ )
{
result.Add(input[i]);
}
return result.ToArray();
}
