Javascript making the return of a function into a variable

Question

How can I make this app.locals.user to be the return value instead of a function? Right now I have to run app.locals.user().name.

How can I make it so I can just run app.locals.user.name?

    app.locals.user = function(){
            if(typeof(req.session.user) != 'undefined'){
                console.log(req.session.user.name.full);
                return req.session.user;
            }else{
                return false;
            }
        };

djechlin · Accepted Answer · 2012-05-24 21:16:35Z

2

just return whateverVariable;

Javascript isn't typed so you can't really do anything to put this in the function signature.

function foo() {
    var x = { a : 10, b : 20};
    return x;
}

var y = foo();
debug(y.a);  //prints 10

answered May 24, 2012 at 21:16

djechlin

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1 Comment

Vartan Arabyan Over a year ago

well at the moment I am returning the function, is there a way i can make it a inline variable?

Romain Meresse · Accepted Answer · 2012-05-25 09:47:05Z

1

Well, you could use __defineGetter__ :

app.locals.__defineGetter__("user", function() {
    if(typeof(req.session.user) != 'undefined') {
        console.log(req.session.user.name.full);
        return req.session.user;
    } else {
        return false;
    }
});

Edit : __defineGetter__ seems to be deprecated, here is a better way :

Object.defineProperty(app.locals, "user", { get : function() {
    if(typeof(req.session.user) != 'undefined') {
        console.log(req.session.user.name.full);
        return req.session.user;
    } else {
        return false;
    }
});

edited May 25, 2012 at 9:47

answered May 25, 2012 at 9:31

Romain Meresse

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Comments

Zach · Accepted Answer · 2012-05-24 22:17:28Z

1

You can immediately execute the function in order to store the result as a variable:

 app.locals.user = (function(){
            if(typeof(req.session.user) != 'undefined'){
                console.log(req.session.user.name.full);
                return req.session.user;
            }else{
                return false;
            }
        })();

answered May 24, 2012 at 22:17

Zach

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1 Comment

Zach Over a year ago

@VartanArabyan, that's true, but I thought that's what you were asking for. You cannot have a variable that automatically updates itself -- if that's what you want, then make it a function and call it every time.

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