How to .load to a php page an array?

Question

How could I sent to a php page the array titolari?

var titolari = $('#titolari').sortable('toArray');
$("#formazione-realtime").load('formazione-realtime.inc.php', {
    "$titolari[]" : titolari
});

The php page is loaded correctly, but the php page seems not to receive the array... how do I take it into my php script?

The code you are showing is javascript, not PHP. Elaborate on your code (with more of the JS or PHP) and question please. — PenguinCoder
– PenguinCoder, Commented May 31, 2012 at 17:12

Emil Vikström · Accepted Answer · 2012-05-31 17:20:38Z

1

As you can see in the jQuery documentation, the call will use the POST method if data is added as an object.

On the client:

var titolari = $('#titolari').sortable('toArray');
$("#formazione-realtime").load('formazione-realtime.inc.php', {
    "titolari" : titolari
});

On the server:

$titolari = $_POST['titolari'];

edited May 31, 2012 at 17:20

answered May 31, 2012 at 17:13

Emil Vikström

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10 Comments

Tom Over a year ago

Like this: <?php $titolari = $_GET['titolari']; for ($i = 1; $i <= 300; $i++) { echo $titolari[$i]; } ?> It doesn't echo anything...

Emil Vikström Over a year ago

Tommaso, my apologies! A bit down in the documentation I found this: "The POST method is used if data is provided as an object". I have updated my answer.

Tom Over a year ago

I'd like to specify that jQuery load formazione-realtime.inc.php, and this php page echos in the same page of jQuery. I don't know if it's a problem for _POST. And also titolari is an Array.

Emil Vikström Over a year ago

Then I'm afraid I know too little about jQuery to help you here. Maybe you can provide a full test case in your question?

user1299518 Over a year ago

just for test, this brings anything home? $.post("formazione-realtime.inc.php",{"titolari" : titolari})

|

Nick Caballero · Accepted Answer · 2012-06-01 01:34:11Z

0

Javascript

$.ajax({
    url:'formazione-realtime.inc.php',
    data:{
        'titolari':['ti','to','la','ri']
    },
    context:{},
    type:'POST',
    contentType:'json',
    success:function(data) {
        console.log(data);
        $("#formazione-realtime").html(data);
    },
    error:function() {
        //Handle this
    }
};

PHP

try{
    $vars = json_decode(file_get_contents('php://input'), 1);
catch(Exception $e) {
    //Handle this
}
print_r($vars);
exit;

edited Jun 1, 2012 at 1:34

answered May 31, 2012 at 17:53

Nick Caballero

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